A small mass m is attached to a massless string whose other end is fixed at P as shown in figure. The mass is undergoing circular motion in x-y plane with centre O and constant angular speed
. If the angular momentum of the system, calculated about O and P and denoted by
and
respectively, then

Text Solution
Verified by ExpertsC
In figure, weight mg of the mass acts vertically downwards and tension T in the string acts along KP. Two rectangular components of T are
opposite to mg and
along KO.

About O, torques due to T
and mg cancel out. Torque due to
is zero. Therefore, net torque about O is zero.
As 
is not central force is zero
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